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我最近开始使用 argp，但我找不到让我的选项成为必需的方法。我想在没有给出 -u (--url) 和 -w (--wordlist) 时查看帮助。为了使我的程序正常工作，他们都需要。我在互联网上查看，但在其他任何地方都找不到同样的问题。谢谢您的帮助

argp.c

#include "../header/argp.h"

#include <argp.h>
#include <stdbool.h>
#include <string.h>
#include <stdlib.h>

const char *argp_program_version = "WiBreak 0.0.1";
static char doc[] = "Program used to brute force URL.";
static char args_doc[] = "[-u URL] [-w WORDLIST]";
static struct argp_option options[] = {
    {"url", 'u', "URL_TO_QUERY", 0, "Compare lines instead of characters."},
    {"wordlist", 'w', "WORDLIST", 0, "Compare words instead of characters."},
    {"verbose", 'v', 0, OPTION_ARG_OPTIONAL, "Show more info"},
    {0}};


// TODO: Need to handle when no argument are given.
static error_t parse_opt(int key, char *arg, struct argp_state *state) {
    struct arguments *arguments = state->input;
    int *arg_cout = state->input;
    switch (key) {
        case 'u':
            arguments->url_to_query = arg;
            // printf("arg : %s\n", arg);
            break;
        case 'w':
            arguments->wordlist = arg;
            break;
        case 'v':
            arguments->verbose = 1;
            break;
        default:
            // argp_usage(state);
            return ARGP_ERR_UNKNOWN;
    }
    // Code never reach even when i initialyze arguments in the main.
    if (arguments->wordlist == "" || arguments->url_to_query == ""){
        argp_failure(state, 1, 0, "too few arguments");
        exit(ARGP_ERR_UNKNOWN);
    }
    
    return 0;
}

struct argp argp = {options, parse_opt, args_doc, doc};

argp.h

#ifndef __ARGP__H
#define __ARGP__H
#include <argp.h>
#include <stdbool.h>

// static error_t parse_opt(int key, char *arg, struct argp_state *state)
extern struct argp argp;

struct arguments {
    // enum { CHARACTER_MODE, WORD_MODE, LINE_MODE } mode;
    char *wordlist;
    char *url_to_query;
    bool verbose;
    // bool isCaseInsensitive;
};


#endif

主程序

int main(int argc, char *argv[]) {
    struct arguments arguments;

    // arguments.mode = CHARACTER_MODE;
    // arguments.isCaseInsensitive = false;
    arguments.wordlist = "";
    arguments.url_to_query = "";

    argp_parse(&argp, argc, argv, 0, 0, &arguments);

    // printf("Wordlist : %s, Url : %s\n", arguments.wordlist,
    // arguments.url_to_query);
    // ...
}

编辑

结果我设法通过更改 parse_opt 来回答我的问题，如下所示

case ARGP_KEY_END:
            // printf("arguments->wordlist : %s, arguments->url_to_query : %s\n", arguments->wordlist, arguments->url_to_query);
            if (arguments->wordlist == NULL || arguments->url_to_query == NULL){
                argp_failure(state, 1, 0, "required -u and -w. See --help for more information");
                exit(ARGP_ERR_UNKNOWN);
            }
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0 回答 0