5

我有包含字段xyz的文档

{ term: "puppies", page: { skip: 1, per_page: 20 } } // not useful as a composite key...
{ page: { skip: 1, per_page: 20 }, term: "puppies" } // different order, same contents

为了确定 xyz 中的“顶级”值,我想将它们全部映射到类似的东西

emit('term="puppies",page={ skip: 1, per_page: 20 }', 1); // composite key

但我无法将嵌入的对象转换为有意义的字符串:

emit('term="puppies",page=[object bson_object]', 1); // not useful

对使用函数而不是 的任何建议toString()

# return the top <num> values of <field> based on a query <selector>
#
# example: top(10, :xyz, {}, {})
def top(num, field, selector, opts = {})
  m = ::BSON::Code.new <<-EOS
    function() {

      var keys = [];

      for (var key in this.#{field}) {
        keys.push(key);
      }

      keys.sort ();

      var sortedKeyValuePairs = [];

      for (i in keys) {
        var key = keys[i];
        var value = this.#{field}[key];

        if (value.constructor.name == 'String') {
          var stringifiedValue = value;
        } else if (value.constructor.name == 'bson_object') {
          // this just says "[object bson_object]" which is not useful
          var stringifiedValue = value.toString();
        } else {
          var stringifiedValue = value.toString();
        }

        sortedKeyValuePairs.push([key, stringifiedValue].join('='));
      }

      // hopefully we'll end up with something like
      // emit("term=puppies,page={skip:1, per_page:20}")
      // instead of
      // emit("term=puppies,page=[object bson_object]")
      emit(sortedKeyValuePairs.join(','), 1);
    }
  EOS
  r = ::BSON::Code.new <<-EOS
    function(k, vals) {
      var sum=0;
      for (var i in vals) sum += vals[i];
      return sum;
    }
  EOS
  docs = []
  collection.map_reduce(m, r, opts.merge(:query => selector)).find({}, :limit => num, :sort => [['value', ::Mongo::DESCENDING]]).each do |doc|
    docs.push doc
  end
  docs
end
4

2 回答 2

7

鉴于MongoDB 使用 SpiderMonkey 作为其内部 JS 引擎,您不能使用JSON.stringify(即使/当 MongoDB切换到 V8时也可以使用)或 SpiderMonkey 的非标准toSource方法

(抱歉,无法在 ATM 上试用以确认它可以工作)

于 2011-04-22T01:06:45.433 回答
1

toSource 方法将完成这项工作,但它也添加了括号。对于干净的文档使用:

value.toSource().substring(1, value.toSource().length - 1)
于 2016-08-15T09:12:07.057 回答