2

我在默认情况下分离子进程的Windows 上使用永远监视器。

在我的应用程序中，我有一个monitor.js监视文件的server.js文件，并且我希望能够server.js在我通过退出monitor.js（Ctrl + C在命令行上点击）关闭应用程序时进行通知。

这是我的演示代码：

监视器.js

const path = require('path');
const forever = require('forever-monitor');

let child;

function exit() {
  console.error('Received exit signal on main process.');
  if (child) {
    // TODO: Here I want to notify the "child", so that it can gracefully shutdown my server
    child.stop();
  }
  process.exit(0);
}

['SIGINT', 'SIGKILL', 'SIGTERM'].forEach(signal => process.on(signal, exit));

child = new forever.Monitor(path.join(__dirname, 'server.js'));
child.start();

服务器.js

const express = require('express');

const app = express();
const port = process.env.PORT || 8080;

let server;

function stopServer() {
  if (server) {
    console.log('Shutting down server...');
    server.close();
  }
}

app.get('/', (request, response) => response.send('Hello'));
server = app.listen(port, () => console.log(`Server is running on port "${port}".`));

收到电话stopServer时如何打电话？server.jsmonitor.jsSIGINT

4

1 回答 1

2

秘诀是使用选项“fork”启动子进程。

使用“fork”选项可以通过调用从父进程向子进程发送消息child.send。这提供了在子进程中侦听close来自父进程的自定义消息的能力，以便子进程可以停止服务器并使用自定义退出代码退出1337。

当父/主进程意识到子进程已经被代码关闭时1337，那么主进程也会关闭。

这是我的解决方案：

监视器.js

const path = require('path');
const forever = require('forever-monitor');

let child;

function exit(signal) {
  console.error(`Received "${signal}" signal on main process.`);
  if (child) {
    child.send({action: 'close'});
  }
}

['SIGINT', 'SIGKILL', 'SIGTERM'].forEach(signal => process.on(signal, () => exit(signal)));

process.on('exit', (code) => console.log(`Stopped main process with code "${code}".`));

const options = {fork: true};

child = new forever.Monitor(path.join(__dirname, 'server.js'), options);

child.on('exit:code', (code) => {
  if (code === 1337) {
    if (child) {
      child.stop();
      console.log('Successfully stopped child process.');
    }
    console.log('Stopping main process ...');
    process.exit(0);
  }
});

child.start();

服务器.js

const express = require('express');

const app = express();
const port = process.env.PORT || 8080;

let server;

if (process.send) {
  process.on('message', function (message) {
    console.log(`Received "${message.action}" message from main process.`);
    if (message.action === 'close') {
      stopServer();
    }
  });
}

function stopServer() {
  if (server) {
    console.log('Stopping server in child process ...');
    server.close(() => {
      console.log('Stopped server in child process.');
      process.exit(1337);
    });
  }
}

app.get('/', (request, response) => response.send('Hello'));
server = app.listen(port, () => console.log(`Server is running on port "${port}".`));
于 2018-05-10T12:21:44.420 回答