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我想在 Swift 中定义一个NSCharacterSet包含:[A-Z](注意双字节,这不是 [AZ])。

这样做的正确语法是什么?下面我在 Objectiv C 中工作的代码似乎并不那么容易转换为 Swift。

    NSRange alphaDoubleByteRange;
    NSMutableCharacterSet *alphaDoubleByteLetters;
    alphaDoubleByteRange.location = (unsigned int)[@"A" characterAtIndex:0];
    alphaDoubleByteRange.length = 26;
    alphaDoubleByteLetters = [[NSMutableCharacterSet alloc] init];
    [alphaDoubleByteLetters formUnionWithCharacterSet:[NSCharacterSet characterSetWithRange:alphaDoubleByteRange]];
    // Now alphaDoubleByteLetters contains what I want.
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1 回答 1

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您可以从 unicode 标量值的范围创建字符集:

let firstCode = Int("A".unicodeScalars.first!.value)
let lastCode =  Int("Z".unicodeScalars.first!.value)
let alphaDoubleByteRange = NSRange(location: firstCode, length: lastCode - firstCode + 1)
let alphaDoubleByteLetters = NSCharacterSet(range: alphaDoubleByteRange)

或者,在Unicode 表中查找字符并直接使用标量值:

let firstCode = 0xFF21  // "A"
let lastCode =  0xFF3A  // "Z"
// ...
于 2016-08-16T07:58:51.163 回答