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我有一个使用火花流的项目,我正在使用“火花提交”运行它,但我遇到了这个错误:

15/01/14 10:34:18 ERROR ReceiverTracker: Deregistered receiver for stream 0: Error starting receiver 0 - java.lang.AbstractMethodError
    at org.apache.spark.Logging$class.log(Logging.scala:52)
    at org.apache.spark.streaming.kafka.KafkaReceiver.log(KafkaInputDStream.scala:66)
    at org.apache.spark.Logging$class.logInfo(Logging.scala:59)
    at org.apache.spark.streaming.kafka.KafkaReceiver.logInfo(KafkaInputDStream.scala:66)
    at org.apache.spark.streaming.kafka.KafkaReceiver.onStart(KafkaInputDStream.scala:86)
    at org.apache.spark.streaming.receiver.ReceiverSupervisor.startReceiver(ReceiverSupervisor.scala:121)
    at org.apache.spark.streaming.receiver.ReceiverSupervisor.start(ReceiverSupervisor.scala:106)
    at org.apache.spark.streaming.scheduler.ReceiverTracker$ReceiverLauncher$$anonfun$9.apply(ReceiverTracker.scala:264)
    at org.apache.spark.streaming.scheduler.ReceiverTracker$ReceiverLauncher$$anonfun$9.apply(ReceiverTracker.scala:257)
    at org.apache.spark.SparkContext$$anonfun$runJob$4.apply(SparkContext.scala:1121)
    at org.apache.spark.SparkContext$$anonfun$runJob$4.apply(SparkContext.scala:1121)
    at org.apache.spark.scheduler.ResultTask.runTask(ResultTask.scala:62)
    at org.apache.spark.scheduler.Task.run(Task.scala:54)
    at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:177)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
    at java.lang.Thread.run(Thread.java:745)

这是错误来自的代码,一切都运行良好,直到 ssc.start()

    val Array(zkQuorum, group, topics, numThreads) = args
    val sparkConf = new SparkConf().setAppName("Jumbly_StreamingConsumer")
    val ssc = new StreamingContext(sparkConf, Seconds(2))
    ssc.checkpoint("checkpoint")
    .
    .
    .
    ssc.start()
    ssc.awaitTermination()

我已经使用“spark-submit”运行了 SparkPi 示例,它运行良好,所以我似乎无法弄清楚是什么导致了我的应用程序出现问题,任何帮助将不胜感激。

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1 回答 1

3

从以下文档java.lang.AbstractMethod

通常,这个错误会被编译器捕获;如果自上次编译当前执行的方法以来某些类的定义发生了不兼容的更改,则此错误只会在运行时发生。

这意味着编译和运行时依赖项之间存在版本不兼容。确保对齐这些版本以解决此问题。

于 2015-01-15T10:05:22.870 回答