3

我在 javascript 中创建了一个计时器应用程序。首先，它需要当前的 UTC 日期来启动计时器并提供一些参考。这是代码

on_timer: function(e) {
            var self = this;
            if ($(e.target).hasClass("pt_timer_start")) {
                var current_date = this.get_current_UTCDate();
                this.project_timesheet_db.set_current_timer_activity({date: current_date});
                this.start_interval();
                this.initialize_timer();
                this.$el.find(".pt_timer_start,.pt_timer_stop").toggleClass("o_hidden");

现在，一旦定时器启动，并且在一段时间后，定时器参考上述on_timer: function(e)功能有一些经过的时间。

这个功能是

start_interval: function() {
            var timer_activity = this.project_timesheet_db.get_current_timer_activity();
            var self = this;
            this.intervalTimer = setInterval(function(){
                self.$el.find(".pt_duration").each(function() {
                    var el_hour = $(this).find("span.hours");
                    var el_minute = $(this).find("span.minutes");
                    var minute = parseInt(el_minute.text());
                    if(minute >= 60) {
                        el_hour.text(_.str.sprintf("%02d", parseInt(el_hour.text()) + 1));
                        minute = 0;
                    }
                    el_minute.text(_.str.sprintf("%02d", minute));
                    var el_second = $(this).find("span.seconds");
                    var seconds = parseInt(el_second.text()) + 1;
                    if(seconds > 60) {
                        el_minute.text(_.str.sprintf("%02d", parseInt(el_minute.text()) + 1));
                        seconds = 0;
                    }
                    el_second.text(_.str.sprintf("%02d", seconds));
                });
            }, 1000);
        },

现在，考虑el_hour，el_minute，el_seconds如何以 HH:MM:SS 方式计算初始时间和当前计时器值之间的时间差。

提前感谢您的帮助

4

5 回答 5

12

要将 H:M:S 转换为秒，您可以使用一个简单的函数，例如：

// Convert H:M:S to seconds
// Seconds are optional (i.e. n:n is treated as h:s)
function hmsToSeconds(s) {
  var b = s.split(':');
  return b[0]*3600 + b[1]*60 + (+b[2] || 0);
}

然后将秒转换回 HMS：

// Convert seconds to hh:mm:ss
// Allow for -ve time values
function secondsToHMS(secs) {
  function z(n){return (n<10?'0':'') + n;}
  var sign = secs < 0? '-':'';
  secs = Math.abs(secs);
  return sign + z(secs/3600 |0) + ':' + z((secs%3600) / 60 |0) + ':' + z(secs%60);
}

var a = '01:43:28';
var b = '12:22:46';

console.log(secondsToHMS(hmsToSeconds(a) - hmsToSeconds(b)));  // -10:39:18
console.log(secondsToHMS(hmsToSeconds(b) - hmsToSeconds(a)));  //  10:39:18

您可能想要缩写函数名称来表示：

toHMS(toSec(a) - toSec(b));  // -10:39:18

请注意，这不包括时间可能跨越夏令时边界的位置。为此，您需要包含年、月和日的完全限定日期。使用这些值创建日期对象、找出差异、转换为秒并使用secondsToHMS函数。

编辑

问题标题提到了日期，但内容似乎只提到了小时、分钟和秒的字符串。

如果您有 Date 对象，则可以使用以下方法以毫秒为单位获取它们之间的差异：

var diffMilliseconds = date0 - date1;

并转换为秒：

var diffSeconds = diffMilliseconds / 1000;

并使用上面的secondsToHMS函数显示为 HH:MM:SS ：

secondsToHMS((date0 - date1) / 1000);

例如

var d0 = new Date(2014,10,10,1,43,28);
var d1 = new Date(2014,10,10,12,22,46);

console.log( secondsToHMS((d0 - d1) / 1000));  // -10:39:18
于 2014-10-27T03:14:33.837 回答
3

我认为有一个更简单的解决方案。

function dateDiffToString(a, b){

    // make checks to make sure a and b are not null
    // and that they are date | integers types

    diff = Math.abs(a - b);

    ms = diff % 1000;
    diff = (diff - ms) / 1000
    ss = diff % 60;
    diff = (diff - ss) / 60
    mm = diff % 60;
    diff = (diff - mm) / 60
    hh = diff % 24;
    days = (diff - hh) / 24

    return days + ":" + hh+":"+mm+":"+ss+"."+ms;

}

var today = new Date()
var yest = new Date()
    yest = yest.setDate(today.getDate()-1)

console.log(dateDiffToString(yest, today))

于 2018-05-15T02:50:13.137 回答
3 
const dateDiffToString = (a, b) => {
  let diff = Math.abs(a - b);

  let ms = diff % 1000;
  diff = (diff - ms) / 1000;
  let s = diff % 60;
  diff = (diff - s) / 60;
  let m = diff % 60;
  diff = (diff - m) / 60;
  let h = diff;

  let ss = s <= 9 && s >= 0 ? `0${s}` : s;
  let mm = m <= 9 && m >= 0 ? `0${m}` : m;
  let hh = h <= 9 && h >= 0 ? `0${h}` : h;

  return hh + ':' + mm + ':' + ss;
};
于 2020-06-13T17:03:59.217 回答
1

这可能是简单的答案

var d1 = new Date(2014,10,11,1,43,28);
var d2 = new Date(2014,10,11,2,53,58);
var date = new Date(d2-d1);
var hour = date.getUTCHours();
var min = date.getUTCMinutes();
var sec = date.getUTCSeconds();
var day = date.getUTCDate() - 1;
console.log(day + ":" + hour + ":" + min + ":" + sec)

于 2018-11-30T08:47:18.717 回答
0

更直观，更易于阅读。

function hmsToSeconds(t) {
    const [hours, minutes, seconds] = t.split(':')
    return Number(hours) * 60 * 60 + Number(minutes) * 60 + Number(seconds)
  }

function secondsToHMS(secs) {
    return new Date(secs * 1000).toISOString().substr(11, 8)
  }

var startTime = '01:43:28';
var endTime = '12:22:46';

console.log(secondsToHMS(hmsToSeconds(endTime) - hmsToSeconds(startTime))); //10:39:18

于 2021-10-27T03:55:46.887 回答