我正在尝试将Splint与 MySQL C API 一起使用,并且遇到了一些与释放内存有关的其他问题。在我能找到的所有关于使用 C API 的示例中,唯一被调用的释放函数是mysql_free_result
,但行和字段永远不会被释放:
while ((row = mysql_fetch_row(result)))
{
for(int i = 0; i < num_fields; i++)
{
if (i == 0)
{
while(field = mysql_fetch_field(result))
{
// Bla
}
}
}
}
mysql_free_result(result);
mysql_close(con);
Splint 当然会抛出一个错误,指出行和字段是内存泄漏。他们是吗?如何解决这个问题?我应该手动释放行和字段结构吗?
编辑:好的,因为mysql_fetch_row
当没有更多的行时返回 null,我假设它也会从每个循环的前一行中释放所有内存。但我怎么会告诉斯普林特这件事呢?
编辑2:这是mysql_fetch_row
(5.5版)的实现。没有分配内存,该函数只是将您指向下一行。因此,需要一个 Splint 注释来告诉 Splint 没有分配内存,而是共享内存。
MYSQL_ROW STDCALL
mysql_fetch_row(MYSQL_RES *res)
{
DBUG_ENTER("mysql_fetch_row");
if (!res->data)
{ /* Unbufferred fetch */
if (!res->eof)
{
MYSQL *mysql= res->handle;
if (mysql->status != MYSQL_STATUS_USE_RESULT)
{
set_mysql_error(mysql,
res->unbuffered_fetch_cancelled ?
CR_FETCH_CANCELED : CR_COMMANDS_OUT_OF_SYNC,
unknown_sqlstate);
}
else if (!(read_one_row(mysql, res->field_count, res->row, res->lengths)))
{
res->row_count++;
DBUG_RETURN(res->current_row=res->row);
}
DBUG_PRINT("info",("end of data"));
res->eof=1;
mysql->status=MYSQL_STATUS_READY;
/*
Reset only if owner points to us: there is a chance that somebody
started new query after mysql_stmt_close():
*/
if (mysql->unbuffered_fetch_owner == &res->unbuffered_fetch_cancelled)
mysql->unbuffered_fetch_owner= 0;
/* Don't clear handle in mysql_free_result */
res->handle=0;
}
DBUG_RETURN((MYSQL_ROW) NULL);
}
{
MYSQL_ROW tmp;
if (!res->data_cursor)
{
DBUG_PRINT("info",("end of data"));
DBUG_RETURN(res->current_row=(MYSQL_ROW) NULL);
}
tmp = res->data_cursor->data;
res->data_cursor = res->data_cursor->next;
DBUG_RETURN(res->current_row=tmp);
}
}